x^2-725x+625=0

Solution for x^2-725x+625=0 equation:

x^2-725x+625=0

a = 1; b = -725; c = +625;
Δ = b2-4ac
Δ = -7252-4·1·625
Δ = 523125
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{523125}=\sqrt{5625*93}=\sqrt{5625}*\sqrt{93}=75\sqrt{93}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-725)-75\sqrt{93}}{2*1}=\frac{725-75\sqrt{93}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-725)+75\sqrt{93}}{2*1}=\frac{725+75\sqrt{93}}{2}
$